The winning Connecticut Play3 numbers for September 3, 2005 were: night 3-9-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 3, 2005 | Night | 3-9-6 | 18 | 9 |
| Sep 2, 2005 | Night | 3-1-0 | 4 | 4 |
| Sep 2, 2005 | Day | 6-8-9 | 23 | 5 |
| Sep 1, 2005 | Night | 0-6-2 | 8 | 8 |
| Sep 1, 2005 | Day | 3-1-7 | 11 | 2 |
| Aug 31, 2005 | Night | 9-8-6 | 23 | 5 |
| Aug 31, 2005 | Day | 7-9-2 | 18 | 9 |
| Aug 30, 2005 | Night | 5-5-1 | 11 | 2 |
| Aug 30, 2005 | Day | 6-4-9 | 19 | 1 |
| Aug 29, 2005 | Night | 0-6-5 | 11 | 2 |
| Aug 29, 2005 | Day | 7-4-4 | 15 | 6 |
| Aug 28, 2005 | Night | 4-8-3 | 15 | 6 |