The winning Connecticut Play3 numbers for August 7, 2005 were: night 7-0-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 7, 2005 | Night | 7-0-2 | 9 | 9 |
| Aug 6, 2005 | Night | 0-6-8 | 14 | 5 |
| Aug 5, 2005 | Night | 2-0-7 | 9 | 9 |
| Aug 5, 2005 | Day | 7-8-3 | 18 | 9 |
| Aug 4, 2005 | Night | 1-7-7 | 15 | 6 |
| Aug 4, 2005 | Day | 8-8-6 | 22 | 4 |
| Aug 3, 2005 | Night | 5-1-0 | 6 | 6 |
| Aug 3, 2005 | Day | 6-1-4 | 11 | 2 |
| Aug 2, 2005 | Night | 7-5-5 | 17 | 8 |
| Aug 2, 2005 | Day | 4-6-8 | 18 | 9 |
| Aug 1, 2005 | Night | 7-2-9 | 18 | 9 |
| Aug 1, 2005 | Day | 2-5-6 | 13 | 4 |