The winning Connecticut Play3 numbers for December 5, 2004 were: night 4-5-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 5, 2004 | Night | 4-5-9 | 18 | 9 |
| Dec 4, 2004 | Night | 5-3-6 | 14 | 5 |
| Dec 3, 2004 | Night | 8-2-7 | 17 | 8 |
| Dec 3, 2004 | Day | 9-5-3 | 17 | 8 |
| Dec 2, 2004 | Night | 9-0-6 | 15 | 6 |
| Dec 2, 2004 | Day | 7-4-1 | 12 | 3 |
| Dec 1, 2004 | Night | 9-1-3 | 13 | 4 |
| Dec 1, 2004 | Day | 1-5-2 | 8 | 8 |
| Nov 30, 2004 | Night | 5-1-8 | 14 | 5 |
| Nov 30, 2004 | Day | 2-7-0 | 9 | 9 |
| Nov 29, 2004 | Night | 8-4-2 | 14 | 5 |
| Nov 29, 2004 | Day | 3-6-3 | 12 | 3 |