The winning Connecticut Play3 numbers for December 30, 2003 were: day 5-3-0; night 2-3-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 30, 2003 | Night | 2-3-7 | 12 | 3 |
| Dec 30, 2003 | Day | 5-3-0 | 8 | 8 |
| Dec 29, 2003 | Night | 8-6-5 | 19 | 1 |
| Dec 29, 2003 | Day | 3-0-1 | 4 | 4 |
| Dec 28, 2003 | Night | 6-4-5 | 15 | 6 |
| Dec 27, 2003 | Night | 4-7-3 | 14 | 5 |
| Dec 26, 2003 | Night | 4-1-9 | 14 | 5 |
| Dec 26, 2003 | Day | 3-5-6 | 14 | 5 |
| Dec 25, 2003 | Night | 7-5-1 | 13 | 4 |
| Dec 25, 2003 | Day | 4-1-5 | 10 | 1 |
| Dec 24, 2003 | Night | 5-3-0 | 8 | 8 |
| Dec 24, 2003 | Day | 4-6-1 | 11 | 2 |