The winning Connecticut Play3 numbers for December 13, 2003 were: night 8-5-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 13, 2003 | Night | 8-5-1 | 14 | 5 |
| Dec 12, 2003 | Night | 1-6-0 | 7 | 7 |
| Dec 12, 2003 | Day | 5-5-7 | 17 | 8 |
| Dec 11, 2003 | Night | 7-9-3 | 19 | 1 |
| Dec 11, 2003 | Day | 9-5-8 | 22 | 4 |
| Dec 10, 2003 | Night | 4-0-6 | 10 | 1 |
| Dec 10, 2003 | Day | 8-7-2 | 17 | 8 |
| Dec 9, 2003 | Night | 2-7-8 | 17 | 8 |
| Dec 9, 2003 | Day | 3-3-5 | 11 | 2 |
| Dec 8, 2003 | Night | 4-8-7 | 19 | 1 |
| Dec 8, 2003 | Day | 8-5-4 | 17 | 8 |
| Dec 7, 2003 | Night | 1-3-7 | 11 | 2 |