The winning Connecticut Play3 numbers for December 8, 2003 were: day 8-5-4; night 4-8-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 8, 2003 | Night | 4-8-7 | 19 | 1 |
| Dec 8, 2003 | Day | 8-5-4 | 17 | 8 |
| Dec 7, 2003 | Night | 1-3-7 | 11 | 2 |
| Dec 6, 2003 | Night | 3-1-0 | 4 | 4 |
| Dec 5, 2003 | Night | 6-7-9 | 22 | 4 |
| Dec 5, 2003 | Day | 9-7-3 | 19 | 1 |
| Dec 4, 2003 | Night | 4-6-6 | 16 | 7 |
| Dec 4, 2003 | Day | 0-9-5 | 14 | 5 |
| Dec 3, 2003 | Night | 8-1-0 | 9 | 9 |
| Dec 3, 2003 | Day | 8-7-9 | 24 | 6 |
| Dec 2, 2003 | Night | 3-5-5 | 13 | 4 |
| Dec 2, 2003 | Day | 7-0-8 | 15 | 6 |