The winning Connecticut Play3 numbers for November 25, 2003 were: day 0-2-5; night 8-1-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 25, 2003 | Night | 8-1-1 | 10 | 1 |
| Nov 25, 2003 | Day | 0-2-5 | 7 | 7 |
| Nov 24, 2003 | Night | 1-8-5 | 14 | 5 |
| Nov 24, 2003 | Day | 6-1-9 | 16 | 7 |
| Nov 23, 2003 | Night | 6-7-6 | 19 | 1 |
| Nov 22, 2003 | Night | 6-1-9 | 16 | 7 |
| Nov 21, 2003 | Night | 2-3-7 | 12 | 3 |
| Nov 21, 2003 | Day | 0-5-9 | 14 | 5 |
| Nov 20, 2003 | Night | 5-5-2 | 12 | 3 |
| Nov 20, 2003 | Day | 0-6-2 | 8 | 8 |
| Nov 19, 2003 | Night | 3-0-6 | 9 | 9 |
| Nov 19, 2003 | Day | 5-3-7 | 15 | 6 |