The winning Connecticut Play3 numbers for November 18, 2003 were: day 3-9-5; night 0-1-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 18, 2003 | Night | 0-1-3 | 4 | 4 |
| Nov 18, 2003 | Day | 3-9-5 | 17 | 8 |
| Nov 17, 2003 | Night | 9-4-8 | 21 | 3 |
| Nov 17, 2003 | Day | 9-6-3 | 18 | 9 |
| Nov 16, 2003 | Night | 8-7-6 | 21 | 3 |
| Nov 15, 2003 | Night | 5-2-5 | 12 | 3 |
| Nov 14, 2003 | Night | 8-3-4 | 15 | 6 |
| Nov 14, 2003 | Day | 1-4-4 | 9 | 9 |
| Nov 13, 2003 | Night | 2-6-2 | 10 | 1 |
| Nov 13, 2003 | Day | 2-3-8 | 13 | 4 |
| Nov 12, 2003 | Night | 2-6-4 | 12 | 3 |
| Nov 12, 2003 | Day | 7-8-1 | 16 | 7 |