The winning Connecticut Play3 numbers for November 2, 2003 were: night 8-8-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 2, 2003 | Night | 8-8-3 | 19 | 1 |
| Nov 1, 2003 | Night | 9-2-1 | 12 | 3 |
| Oct 31, 2003 | Night | 3-2-9 | 14 | 5 |
| Oct 31, 2003 | Day | 5-0-4 | 9 | 9 |
| Oct 30, 2003 | Night | 4-2-8 | 14 | 5 |
| Oct 30, 2003 | Day | 6-7-0 | 13 | 4 |
| Oct 29, 2003 | Night | 5-3-2 | 10 | 1 |
| Oct 29, 2003 | Day | 1-0-2 | 3 | 3 |
| Oct 28, 2003 | Night | 7-0-4 | 11 | 2 |
| Oct 28, 2003 | Day | 6-2-4 | 12 | 3 |
| Oct 27, 2003 | Night | 0-3-5 | 8 | 8 |
| Oct 27, 2003 | Day | 4-9-6 | 19 | 1 |