The winning Connecticut Play3 numbers for October 25, 2003 were: night 8-6-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 25, 2003 | Night | 8-6-4 | 18 | 9 |
| Oct 24, 2003 | Night | 9-4-9 | 22 | 4 |
| Oct 24, 2003 | Day | 8-0-5 | 13 | 4 |
| Oct 23, 2003 | Night | 4-1-4 | 9 | 9 |
| Oct 23, 2003 | Day | 7-3-2 | 12 | 3 |
| Oct 22, 2003 | Night | 7-3-5 | 15 | 6 |
| Oct 22, 2003 | Day | 9-9-9 | 27 | 9 |
| Oct 21, 2003 | Night | 6-1-6 | 13 | 4 |
| Oct 21, 2003 | Day | 4-3-0 | 7 | 7 |
| Oct 20, 2003 | Night | 4-1-6 | 11 | 2 |
| Oct 20, 2003 | Day | 0-5-0 | 5 | 5 |
| Oct 19, 2003 | Night | 5-8-0 | 13 | 4 |