The winning Connecticut Play3 numbers for October 20, 2003 were: day 0-5-0; night 4-1-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 20, 2003 | Night | 4-1-6 | 11 | 2 |
| Oct 20, 2003 | Day | 0-5-0 | 5 | 5 |
| Oct 19, 2003 | Night | 5-8-0 | 13 | 4 |
| Oct 18, 2003 | Night | 8-3-9 | 20 | 2 |
| Oct 17, 2003 | Night | 6-1-0 | 7 | 7 |
| Oct 17, 2003 | Day | 6-4-1 | 11 | 2 |
| Oct 16, 2003 | Night | 8-7-7 | 22 | 4 |
| Oct 16, 2003 | Day | 1-8-8 | 17 | 8 |
| Oct 15, 2003 | Night | 6-6-0 | 12 | 3 |
| Oct 15, 2003 | Day | 1-0-5 | 6 | 6 |
| Oct 14, 2003 | Night | 4-7-1 | 12 | 3 |
| Oct 14, 2003 | Day | 5-2-9 | 16 | 7 |