The winning Connecticut Play3 numbers for October 11, 2003 were: night 2-4-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 11, 2003 | Night | 2-4-2 | 8 | 8 |
| Oct 10, 2003 | Night | 9-1-5 | 15 | 6 |
| Oct 10, 2003 | Day | 1-0-1 | 2 | 2 |
| Oct 9, 2003 | Night | 0-7-1 | 8 | 8 |
| Oct 9, 2003 | Day | 8-5-2 | 15 | 6 |
| Oct 8, 2003 | Night | 5-7-0 | 12 | 3 |
| Oct 8, 2003 | Day | 0-3-1 | 4 | 4 |
| Oct 7, 2003 | Night | 8-4-7 | 19 | 1 |
| Oct 7, 2003 | Day | 3-7-8 | 18 | 9 |
| Oct 6, 2003 | Night | 3-2-4 | 9 | 9 |
| Oct 6, 2003 | Day | 0-0-9 | 9 | 9 |
| Oct 5, 2003 | Night | 9-1-8 | 18 | 9 |