The winning Connecticut Play3 numbers for October 1, 2003 were: day 5-0-9; night 4-3-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 1, 2003 | Night | 4-3-5 | 12 | 3 |
| Oct 1, 2003 | Day | 5-0-9 | 14 | 5 |
| Sep 30, 2003 | Night | 6-7-5 | 18 | 9 |
| Sep 30, 2003 | Day | 8-9-1 | 18 | 9 |
| Sep 29, 2003 | Night | 7-9-0 | 16 | 7 |
| Sep 29, 2003 | Day | 4-7-3 | 14 | 5 |
| Sep 28, 2003 | Night | 3-8-7 | 18 | 9 |
| Sep 27, 2003 | Night | 3-7-3 | 13 | 4 |
| Sep 26, 2003 | Night | 9-8-0 | 17 | 8 |
| Sep 26, 2003 | Day | 5-6-6 | 17 | 8 |
| Sep 25, 2003 | Night | 8-0-5 | 13 | 4 |
| Sep 25, 2003 | Day | 3-0-3 | 6 | 6 |