The winning Connecticut Play3 numbers for September 27, 2003 were: night 3-7-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 27, 2003 | Night | 3-7-3 | 13 | 4 |
| Sep 26, 2003 | Night | 9-8-0 | 17 | 8 |
| Sep 26, 2003 | Day | 5-6-6 | 17 | 8 |
| Sep 25, 2003 | Night | 8-0-5 | 13 | 4 |
| Sep 25, 2003 | Day | 3-0-3 | 6 | 6 |
| Sep 24, 2003 | Night | 7-0-7 | 14 | 5 |
| Sep 24, 2003 | Day | 7-1-1 | 9 | 9 |
| Sep 23, 2003 | Night | 6-1-3 | 10 | 1 |
| Sep 23, 2003 | Day | 5-3-6 | 14 | 5 |
| Sep 22, 2003 | Night | 4-9-5 | 18 | 9 |
| Sep 22, 2003 | Day | 8-9-7 | 24 | 6 |
| Sep 21, 2003 | Night | 8-5-6 | 19 | 1 |