The winning Connecticut Play3 numbers for September 21, 2003 were: night 8-5-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 21, 2003 | Night | 8-5-6 | 19 | 1 |
| Sep 20, 2003 | Night | 9-1-2 | 12 | 3 |
| Sep 19, 2003 | Night | 8-3-7 | 18 | 9 |
| Sep 19, 2003 | Day | 2-6-4 | 12 | 3 |
| Sep 18, 2003 | Night | 7-4-5 | 16 | 7 |
| Sep 18, 2003 | Day | 8-7-6 | 21 | 3 |
| Sep 17, 2003 | Night | 8-3-4 | 15 | 6 |
| Sep 17, 2003 | Day | 8-9-7 | 24 | 6 |
| Sep 16, 2003 | Night | 5-7-2 | 14 | 5 |
| Sep 16, 2003 | Day | 6-1-1 | 8 | 8 |
| Sep 15, 2003 | Night | 6-6-4 | 16 | 7 |
| Sep 15, 2003 | Day | 9-6-4 | 19 | 1 |