The winning Connecticut Play3 numbers for September 16, 2003 were: day 6-1-1; night 5-7-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 16, 2003 | Night | 5-7-2 | 14 | 5 |
| Sep 16, 2003 | Day | 6-1-1 | 8 | 8 |
| Sep 15, 2003 | Night | 6-6-4 | 16 | 7 |
| Sep 15, 2003 | Day | 9-6-4 | 19 | 1 |
| Sep 14, 2003 | Night | 5-8-9 | 22 | 4 |
| Sep 13, 2003 | Night | 0-0-8 | 8 | 8 |
| Sep 12, 2003 | Night | 6-1-1 | 8 | 8 |
| Sep 12, 2003 | Day | 3-7-6 | 16 | 7 |
| Sep 11, 2003 | Night | 6-3-9 | 18 | 9 |
| Sep 11, 2003 | Day | 0-3-6 | 9 | 9 |
| Sep 10, 2003 | Night | 8-1-5 | 14 | 5 |
| Sep 10, 2003 | Day | 6-6-2 | 14 | 5 |