The winning Connecticut Play3 numbers for September 13, 2003 were: night 0-0-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 13, 2003 | Night | 0-0-8 | 8 | 8 |
| Sep 12, 2003 | Night | 6-1-1 | 8 | 8 |
| Sep 12, 2003 | Day | 3-7-6 | 16 | 7 |
| Sep 11, 2003 | Night | 6-3-9 | 18 | 9 |
| Sep 11, 2003 | Day | 0-3-6 | 9 | 9 |
| Sep 10, 2003 | Night | 8-1-5 | 14 | 5 |
| Sep 10, 2003 | Day | 6-6-2 | 14 | 5 |
| Sep 9, 2003 | Night | 5-9-4 | 18 | 9 |
| Sep 9, 2003 | Day | 9-3-7 | 19 | 1 |
| Sep 8, 2003 | Night | 7-4-4 | 15 | 6 |
| Sep 8, 2003 | Day | 8-7-8 | 23 | 5 |
| Sep 7, 2003 | Night | 6-9-9 | 24 | 6 |