The winning Connecticut Play3 numbers for September 8, 2003 were: day 8-7-8; night 7-4-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 8, 2003 | Night | 7-4-4 | 15 | 6 |
| Sep 8, 2003 | Day | 8-7-8 | 23 | 5 |
| Sep 7, 2003 | Night | 6-9-9 | 24 | 6 |
| Sep 6, 2003 | Night | 3-5-5 | 13 | 4 |
| Sep 5, 2003 | Night | 4-8-7 | 19 | 1 |
| Sep 5, 2003 | Day | 9-3-8 | 20 | 2 |
| Sep 4, 2003 | Night | 2-2-5 | 9 | 9 |
| Sep 4, 2003 | Day | 0-3-5 | 8 | 8 |
| Sep 3, 2003 | Night | 9-8-8 | 25 | 7 |
| Sep 3, 2003 | Day | 4-9-3 | 16 | 7 |
| Sep 2, 2003 | Night | 6-1-0 | 7 | 7 |
| Sep 2, 2003 | Day | 1-4-2 | 7 | 7 |