The winning Connecticut Play3 numbers for August 30, 2003 were: night 4-1-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 30, 2003 | Night | 4-1-9 | 14 | 5 |
| Aug 29, 2003 | Night | 5-2-2 | 9 | 9 |
| Aug 29, 2003 | Day | 8-0-1 | 9 | 9 |
| Aug 28, 2003 | Night | 0-4-8 | 12 | 3 |
| Aug 28, 2003 | Day | 5-5-4 | 14 | 5 |
| Aug 27, 2003 | Night | 4-5-9 | 18 | 9 |
| Aug 27, 2003 | Day | 7-2-6 | 15 | 6 |
| Aug 26, 2003 | Night | 9-9-6 | 24 | 6 |
| Aug 26, 2003 | Day | 7-1-9 | 17 | 8 |
| Aug 25, 2003 | Night | 4-4-0 | 8 | 8 |
| Aug 25, 2003 | Day | 1-0-6 | 7 | 7 |
| Aug 24, 2003 | Night | 4-0-0 | 4 | 4 |