The winning Connecticut Play3 numbers for August 25, 2003 were: day 1-0-6; night 4-4-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 25, 2003 | Night | 4-4-0 | 8 | 8 |
| Aug 25, 2003 | Day | 1-0-6 | 7 | 7 |
| Aug 24, 2003 | Night | 4-0-0 | 4 | 4 |
| Aug 23, 2003 | Night | 1-9-4 | 14 | 5 |
| Aug 22, 2003 | Night | 9-4-8 | 21 | 3 |
| Aug 22, 2003 | Day | 9-5-3 | 17 | 8 |
| Aug 21, 2003 | Night | 5-4-4 | 13 | 4 |
| Aug 21, 2003 | Day | 4-2-3 | 9 | 9 |
| Aug 20, 2003 | Night | 3-8-4 | 15 | 6 |
| Aug 20, 2003 | Day | 2-2-4 | 8 | 8 |
| Aug 19, 2003 | Night | 4-3-4 | 11 | 2 |
| Aug 19, 2003 | Day | 0-1-9 | 10 | 1 |