The winning Connecticut Play3 numbers for August 14, 2003 were: day 9-3-3; night 5-1-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 14, 2003 | Night | 5-1-0 | 6 | 6 |
| Aug 14, 2003 | Day | 9-3-3 | 15 | 6 |
| Aug 13, 2003 | Night | 0-0-6 | 6 | 6 |
| Aug 13, 2003 | Day | 5-9-1 | 15 | 6 |
| Aug 12, 2003 | Night | 4-4-2 | 10 | 1 |
| Aug 12, 2003 | Day | 8-6-5 | 19 | 1 |
| Aug 11, 2003 | Night | 9-8-7 | 24 | 6 |
| Aug 11, 2003 | Day | 3-2-9 | 14 | 5 |
| Aug 10, 2003 | Night | 4-0-7 | 11 | 2 |
| Aug 9, 2003 | Night | 4-6-4 | 14 | 5 |
| Aug 8, 2003 | Night | 5-7-6 | 18 | 9 |
| Aug 8, 2003 | Day | 5-4-7 | 16 | 7 |