The winning Connecticut Play3 numbers for August 10, 2003 were: night 4-0-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 10, 2003 | Night | 4-0-7 | 11 | 2 |
| Aug 9, 2003 | Night | 4-6-4 | 14 | 5 |
| Aug 8, 2003 | Night | 5-7-6 | 18 | 9 |
| Aug 8, 2003 | Day | 5-4-7 | 16 | 7 |
| Aug 7, 2003 | Night | 3-4-1 | 8 | 8 |
| Aug 7, 2003 | Day | 7-3-9 | 19 | 1 |
| Aug 6, 2003 | Night | 0-8-2 | 10 | 1 |
| Aug 6, 2003 | Day | 3-8-8 | 19 | 1 |
| Aug 5, 2003 | Night | 5-4-0 | 9 | 9 |
| Aug 5, 2003 | Day | 1-7-0 | 8 | 8 |
| Aug 4, 2003 | Night | 9-3-6 | 18 | 9 |
| Aug 4, 2003 | Day | 5-0-2 | 7 | 7 |