The winning Connecticut Play3 numbers for July 15, 2003 were: day 2-6-5; night 2-4-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jul 15, 2003 | Night | 2-4-0 | 6 | 6 |
| Jul 15, 2003 | Day | 2-6-5 | 13 | 4 |
| Jul 14, 2003 | Night | 3-3-5 | 11 | 2 |
| Jul 14, 2003 | Day | 1-0-4 | 5 | 5 |
| Jul 13, 2003 | Night | 8-3-5 | 16 | 7 |
| Jul 12, 2003 | Night | 0-6-8 | 14 | 5 |
| Jul 11, 2003 | Night | 3-4-0 | 7 | 7 |
| Jul 11, 2003 | Day | 4-6-2 | 12 | 3 |
| Jul 10, 2003 | Night | 1-7-6 | 14 | 5 |
| Jul 10, 2003 | Day | 5-3-0 | 8 | 8 |
| Jul 9, 2003 | Night | 9-9-0 | 18 | 9 |
| Jul 9, 2003 | Day | 8-5-5 | 18 | 9 |