The winning Connecticut Play3 numbers for July 4, 2003 were: day 0-5-9; night 0-2-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jul 4, 2003 | Night | 0-2-2 | 4 | 4 |
| Jul 4, 2003 | Day | 0-5-9 | 14 | 5 |
| Jul 3, 2003 | Night | 5-6-3 | 14 | 5 |
| Jul 3, 2003 | Day | 1-2-0 | 3 | 3 |
| Jul 2, 2003 | Night | 9-8-0 | 17 | 8 |
| Jul 2, 2003 | Day | 1-2-2 | 5 | 5 |
| Jul 1, 2003 | Night | 3-1-7 | 11 | 2 |
| Jul 1, 2003 | Day | 5-0-7 | 12 | 3 |
| Jun 30, 2003 | Night | 5-5-9 | 19 | 1 |
| Jun 30, 2003 | Day | 3-2-8 | 13 | 4 |
| Jun 29, 2003 | Night | 5-5-9 | 19 | 1 |
| Jun 28, 2003 | Night | 8-3-9 | 20 | 2 |