The winning Connecticut Play3 numbers for March 22, 2003 were: night 3-4-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 22, 2003 | Night | 3-4-8 | 15 | 6 |
| Mar 21, 2003 | Night | 4-1-2 | 7 | 7 |
| Mar 21, 2003 | Day | 8-1-6 | 15 | 6 |
| Mar 20, 2003 | Night | 5-6-6 | 17 | 8 |
| Mar 20, 2003 | Day | 4-6-2 | 12 | 3 |
| Mar 19, 2003 | Night | 3-1-5 | 9 | 9 |
| Mar 19, 2003 | Day | 9-8-6 | 23 | 5 |
| Mar 18, 2003 | Night | 7-6-1 | 14 | 5 |
| Mar 18, 2003 | Day | 3-4-5 | 12 | 3 |
| Mar 17, 2003 | Night | 5-5-5 | 15 | 6 |
| Mar 17, 2003 | Day | 5-7-1 | 13 | 4 |
| Mar 16, 2003 | Night | 2-4-7 | 13 | 4 |