The winning Connecticut Play3 numbers for March 16, 2003 were: night 2-4-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 16, 2003 | Night | 2-4-7 | 13 | 4 |
| Mar 15, 2003 | Night | 7-4-5 | 16 | 7 |
| Mar 14, 2003 | Night | 8-1-6 | 15 | 6 |
| Mar 14, 2003 | Day | 0-5-0 | 5 | 5 |
| Mar 13, 2003 | Night | 9-0-5 | 14 | 5 |
| Mar 13, 2003 | Day | 6-1-5 | 12 | 3 |
| Mar 12, 2003 | Night | 8-2-2 | 12 | 3 |
| Mar 12, 2003 | Day | 5-7-6 | 18 | 9 |
| Mar 11, 2003 | Night | 7-9-9 | 25 | 7 |
| Mar 11, 2003 | Day | 6-1-2 | 9 | 9 |
| Mar 10, 2003 | Night | 4-9-1 | 14 | 5 |
| Mar 10, 2003 | Day | 9-7-4 | 20 | 2 |