The winning Connecticut Play3 numbers for March 1, 2003 were: night 5-5-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 1, 2003 | Night | 5-5-9 | 19 | 1 |
| Feb 28, 2003 | Night | 7-7-5 | 19 | 1 |
| Feb 28, 2003 | Day | 5-0-4 | 9 | 9 |
| Feb 27, 2003 | Night | 0-5-7 | 12 | 3 |
| Feb 27, 2003 | Day | 5-6-2 | 13 | 4 |
| Feb 26, 2003 | Night | 2-7-8 | 17 | 8 |
| Feb 26, 2003 | Day | 3-8-8 | 19 | 1 |
| Feb 25, 2003 | Night | 7-6-5 | 18 | 9 |
| Feb 25, 2003 | Day | 7-9-6 | 22 | 4 |
| Feb 24, 2003 | Night | 4-7-7 | 18 | 9 |
| Feb 24, 2003 | Day | 1-4-8 | 13 | 4 |
| Feb 23, 2003 | Night | 3-2-3 | 8 | 8 |