The winning Connecticut Play3 numbers for January 19, 2003 were: night 1-2-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jan 19, 2003 | Night | 1-2-0 | 3 | 3 |
| Jan 18, 2003 | Night | 9-7-1 | 17 | 8 |
| Jan 17, 2003 | Night | 8-5-0 | 13 | 4 |
| Jan 17, 2003 | Day | 4-4-7 | 15 | 6 |
| Jan 16, 2003 | Night | 9-8-6 | 23 | 5 |
| Jan 16, 2003 | Day | 3-6-2 | 11 | 2 |
| Jan 15, 2003 | Night | 0-0-4 | 4 | 4 |
| Jan 15, 2003 | Day | 9-5-9 | 23 | 5 |
| Jan 14, 2003 | Night | 5-4-7 | 16 | 7 |
| Jan 14, 2003 | Day | 4-2-9 | 15 | 6 |
| Jan 13, 2003 | Night | 4-4-1 | 9 | 9 |
| Jan 13, 2003 | Day | 5-8-7 | 20 | 2 |