The winning Connecticut Play3 numbers for January 11, 2003 were: night 0-0-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jan 11, 2003 | Night | 0-0-0 | 0 | 0 |
| Jan 10, 2003 | Night | 8-0-8 | 16 | 7 |
| Jan 10, 2003 | Day | 2-7-9 | 18 | 9 |
| Jan 9, 2003 | Night | 0-7-4 | 11 | 2 |
| Jan 9, 2003 | Day | 8-9-7 | 24 | 6 |
| Jan 8, 2003 | Night | 8-6-7 | 21 | 3 |
| Jan 8, 2003 | Day | 1-5-7 | 13 | 4 |
| Jan 7, 2003 | Night | 2-7-9 | 18 | 9 |
| Jan 7, 2003 | Day | 1-8-4 | 13 | 4 |
| Jan 6, 2003 | Night | 8-1-1 | 10 | 1 |
| Jan 6, 2003 | Day | 7-2-1 | 10 | 1 |
| Jan 5, 2003 | Night | 7-3-0 | 10 | 1 |