The winning Connecticut Play3 numbers for January 5, 2003 were: night 7-3-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jan 5, 2003 | Night | 7-3-0 | 10 | 1 |
| Jan 4, 2003 | Night | 8-3-2 | 13 | 4 |
| Jan 3, 2003 | Night | 8-7-9 | 24 | 6 |
| Jan 3, 2003 | Day | 9-2-0 | 11 | 2 |
| Jan 2, 2003 | Night | 2-8-2 | 12 | 3 |
| Jan 2, 2003 | Day | 1-8-3 | 12 | 3 |
| Jan 1, 2003 | Night | 1-4-8 | 13 | 4 |
| Jan 1, 2003 | Day | 7-0-6 | 13 | 4 |
| Dec 31, 2002 | Night | 9-9-3 | 21 | 3 |
| Dec 31, 2002 | Day | 4-9-6 | 19 | 1 |
| Dec 30, 2002 | Night | 4-0-0 | 4 | 4 |
| Dec 30, 2002 | Day | 6-0-2 | 8 | 8 |