The winning Connecticut Play3 numbers for December 28, 2002 were: night 4-4-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 28, 2002 | Night | 4-4-1 | 9 | 9 |
| Dec 27, 2002 | Night | 9-2-6 | 17 | 8 |
| Dec 27, 2002 | Day | 4-2-3 | 9 | 9 |
| Dec 26, 2002 | Night | 7-4-4 | 15 | 6 |
| Dec 26, 2002 | Day | 2-5-6 | 13 | 4 |
| Dec 25, 2002 | Night | 8-1-2 | 11 | 2 |
| Dec 25, 2002 | Day | 6-7-8 | 21 | 3 |
| Dec 24, 2002 | Night | 9-3-9 | 21 | 3 |
| Dec 24, 2002 | Day | 2-0-5 | 7 | 7 |
| Dec 23, 2002 | Night | 5-5-9 | 19 | 1 |
| Dec 23, 2002 | Day | 6-2-2 | 10 | 1 |
| Dec 22, 2002 | Night | 0-9-5 | 14 | 5 |