The winning Connecticut Play3 numbers for December 16, 2002 were: day 4-9-2; night 4-0-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 16, 2002 | Night | 4-0-5 | 9 | 9 |
| Dec 16, 2002 | Day | 4-9-2 | 15 | 6 |
| Dec 15, 2002 | Night | 0-4-5 | 9 | 9 |
| Dec 14, 2002 | Night | 3-7-0 | 10 | 1 |
| Dec 13, 2002 | Night | 5-6-4 | 15 | 6 |
| Dec 13, 2002 | Day | 5-1-2 | 8 | 8 |
| Dec 12, 2002 | Night | 3-3-5 | 11 | 2 |
| Dec 12, 2002 | Day | 3-9-9 | 21 | 3 |
| Dec 11, 2002 | Night | 8-4-7 | 19 | 1 |
| Dec 11, 2002 | Day | 3-7-5 | 15 | 6 |
| Dec 10, 2002 | Night | 5-6-1 | 12 | 3 |
| Dec 10, 2002 | Day | 4-9-3 | 16 | 7 |