The winning Connecticut Play3 numbers for December 6, 2002 were: day 3-7-5; night 8-9-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 6, 2002 | Night | 8-9-3 | 20 | 2 |
| Dec 6, 2002 | Day | 3-7-5 | 15 | 6 |
| Dec 5, 2002 | Night | 8-3-8 | 19 | 1 |
| Dec 5, 2002 | Day | 1-4-6 | 11 | 2 |
| Dec 4, 2002 | Night | 9-2-4 | 15 | 6 |
| Dec 4, 2002 | Day | 8-5-2 | 15 | 6 |
| Dec 3, 2002 | Night | 4-6-2 | 12 | 3 |
| Dec 3, 2002 | Day | 0-8-0 | 8 | 8 |
| Dec 2, 2002 | Night | 8-7-4 | 19 | 1 |
| Dec 2, 2002 | Day | 2-9-1 | 12 | 3 |
| Dec 1, 2002 | Night | 7-6-8 | 21 | 3 |
| Nov 30, 2002 | Night | 0-6-1 | 7 | 7 |