The winning Connecticut Play3 numbers for November 17, 2002 were: night 4-2-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 17, 2002 | Night | 4-2-3 | 9 | 9 |
| Nov 16, 2002 | Night | 2-8-5 | 15 | 6 |
| Nov 15, 2002 | Night | 9-9-7 | 25 | 7 |
| Nov 15, 2002 | Day | 3-9-3 | 15 | 6 |
| Nov 14, 2002 | Night | 5-5-4 | 14 | 5 |
| Nov 14, 2002 | Day | 6-0-4 | 10 | 1 |
| Nov 13, 2002 | Night | 6-5-6 | 17 | 8 |
| Nov 13, 2002 | Day | 9-9-9 | 27 | 9 |
| Nov 12, 2002 | Night | 7-5-5 | 17 | 8 |
| Nov 12, 2002 | Day | 6-5-5 | 16 | 7 |
| Nov 11, 2002 | Night | 7-2-6 | 15 | 6 |
| Nov 11, 2002 | Day | 5-7-0 | 12 | 3 |