The winning Connecticut Play3 numbers for November 5, 2002 were: day 1-1-6; night 9-7-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 5, 2002 | Night | 9-7-6 | 22 | 4 |
| Nov 5, 2002 | Day | 1-1-6 | 8 | 8 |
| Nov 4, 2002 | Night | 1-6-0 | 7 | 7 |
| Nov 4, 2002 | Day | 6-4-3 | 13 | 4 |
| Nov 3, 2002 | Night | 3-2-9 | 14 | 5 |
| Nov 2, 2002 | Night | 1-2-9 | 12 | 3 |
| Nov 1, 2002 | Night | 9-3-4 | 16 | 7 |
| Nov 1, 2002 | Day | 7-0-8 | 15 | 6 |
| Oct 31, 2002 | Night | 8-3-7 | 18 | 9 |
| Oct 31, 2002 | Day | 7-5-2 | 14 | 5 |
| Oct 30, 2002 | Night | 0-3-7 | 10 | 1 |
| Oct 30, 2002 | Day | 6-0-4 | 10 | 1 |