The winning Connecticut Play3 numbers for October 26, 2002 were: night 2-7-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 26, 2002 | Night | 2-7-4 | 13 | 4 |
| Oct 25, 2002 | Night | 3-4-7 | 14 | 5 |
| Oct 25, 2002 | Day | 7-5-5 | 17 | 8 |
| Oct 24, 2002 | Night | 8-6-3 | 17 | 8 |
| Oct 24, 2002 | Day | 3-4-2 | 9 | 9 |
| Oct 23, 2002 | Night | 0-8-7 | 15 | 6 |
| Oct 23, 2002 | Day | 8-3-8 | 19 | 1 |
| Oct 22, 2002 | Night | 1-3-9 | 13 | 4 |
| Oct 22, 2002 | Day | 0-6-9 | 15 | 6 |
| Oct 21, 2002 | Night | 0-9-2 | 11 | 2 |
| Oct 21, 2002 | Day | 7-2-9 | 18 | 9 |
| Oct 20, 2002 | Night | 0-4-2 | 6 | 6 |