The winning Connecticut Play3 numbers for October 20, 2002 were: night 0-4-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 20, 2002 | Night | 0-4-2 | 6 | 6 |
| Oct 19, 2002 | Night | 6-0-8 | 14 | 5 |
| Oct 18, 2002 | Night | 5-8-5 | 18 | 9 |
| Oct 18, 2002 | Day | 9-3-5 | 17 | 8 |
| Oct 17, 2002 | Night | 8-1-5 | 14 | 5 |
| Oct 17, 2002 | Day | 7-5-0 | 12 | 3 |
| Oct 16, 2002 | Night | 7-1-9 | 17 | 8 |
| Oct 16, 2002 | Day | 3-6-4 | 13 | 4 |
| Oct 15, 2002 | Night | 7-5-5 | 17 | 8 |
| Oct 15, 2002 | Day | 2-6-5 | 13 | 4 |
| Oct 14, 2002 | Night | 8-3-1 | 12 | 3 |
| Oct 14, 2002 | Day | 3-9-0 | 12 | 3 |