The winning Connecticut Play3 numbers for October 13, 2002 were: night 0-5-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 13, 2002 | Night | 0-5-3 | 8 | 8 |
| Oct 12, 2002 | Night | 4-7-2 | 13 | 4 |
| Oct 11, 2002 | Night | 1-2-1 | 4 | 4 |
| Oct 11, 2002 | Day | 5-9-7 | 21 | 3 |
| Oct 10, 2002 | Night | 7-4-9 | 20 | 2 |
| Oct 10, 2002 | Day | 9-6-1 | 16 | 7 |
| Oct 9, 2002 | Night | 8-1-4 | 13 | 4 |
| Oct 9, 2002 | Day | 3-3-7 | 13 | 4 |
| Oct 8, 2002 | Night | 0-9-3 | 12 | 3 |
| Oct 8, 2002 | Day | 2-5-1 | 8 | 8 |
| Oct 7, 2002 | Night | 6-0-7 | 13 | 4 |
| Oct 7, 2002 | Day | 5-2-7 | 14 | 5 |