The winning Connecticut Play3 numbers for October 8, 2002 were: day 2-5-1; night 0-9-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 8, 2002 | Night | 0-9-3 | 12 | 3 |
| Oct 8, 2002 | Day | 2-5-1 | 8 | 8 |
| Oct 7, 2002 | Night | 6-0-7 | 13 | 4 |
| Oct 7, 2002 | Day | 5-2-7 | 14 | 5 |
| Oct 6, 2002 | Night | 8-7-7 | 22 | 4 |
| Oct 5, 2002 | Night | 8-0-6 | 14 | 5 |
| Oct 4, 2002 | Night | 1-2-2 | 5 | 5 |
| Oct 4, 2002 | Day | 9-3-5 | 17 | 8 |
| Oct 3, 2002 | Night | 9-2-3 | 14 | 5 |
| Oct 3, 2002 | Day | 3-8-2 | 13 | 4 |
| Oct 2, 2002 | Night | 4-8-8 | 20 | 2 |
| Oct 2, 2002 | Day | 2-3-4 | 9 | 9 |