The winning Connecticut Play3 numbers for October 1, 2002 were: day 2-2-0; night 4-0-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 1, 2002 | Night | 4-0-5 | 9 | 9 |
| Oct 1, 2002 | Day | 2-2-0 | 4 | 4 |
| Sep 30, 2002 | Night | 6-6-4 | 16 | 7 |
| Sep 30, 2002 | Day | 1-6-8 | 15 | 6 |
| Sep 29, 2002 | Night | 2-7-8 | 17 | 8 |
| Sep 28, 2002 | Night | 4-8-3 | 15 | 6 |
| Sep 27, 2002 | Night | 5-4-4 | 13 | 4 |
| Sep 27, 2002 | Day | 4-4-8 | 16 | 7 |
| Sep 26, 2002 | Night | 5-1-1 | 7 | 7 |
| Sep 26, 2002 | Day | 4-7-2 | 13 | 4 |
| Sep 25, 2002 | Night | 1-6-1 | 8 | 8 |
| Sep 25, 2002 | Day | 9-1-1 | 11 | 2 |