The winning Connecticut Play3 numbers for September 18, 2002 were: day 1-1-9; night 5-3-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 18, 2002 | Night | 5-3-8 | 16 | 7 |
| Sep 18, 2002 | Day | 1-1-9 | 11 | 2 |
| Sep 17, 2002 | Night | 5-4-7 | 16 | 7 |
| Sep 17, 2002 | Day | 7-4-0 | 11 | 2 |
| Sep 16, 2002 | Night | 3-8-0 | 11 | 2 |
| Sep 16, 2002 | Day | 6-3-3 | 12 | 3 |
| Sep 15, 2002 | Night | 3-0-4 | 7 | 7 |
| Sep 14, 2002 | Night | 0-7-7 | 14 | 5 |
| Sep 13, 2002 | Night | 0-1-8 | 9 | 9 |
| Sep 13, 2002 | Day | 8-0-7 | 15 | 6 |
| Sep 12, 2002 | Night | 1-3-7 | 11 | 2 |
| Sep 12, 2002 | Day | 4-5-6 | 15 | 6 |