The winning Connecticut Play3 numbers for September 1, 2002 were: night 2-5-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 1, 2002 | Night | 2-5-0 | 7 | 7 |
| Aug 31, 2002 | Night | 2-8-0 | 10 | 1 |
| Aug 30, 2002 | Night | 5-9-7 | 21 | 3 |
| Aug 30, 2002 | Day | 8-8-1 | 17 | 8 |
| Aug 29, 2002 | Night | 5-0-9 | 14 | 5 |
| Aug 29, 2002 | Day | 4-1-8 | 13 | 4 |
| Aug 28, 2002 | Night | 8-7-0 | 15 | 6 |
| Aug 28, 2002 | Day | 2-6-9 | 17 | 8 |
| Aug 27, 2002 | Night | 6-8-2 | 16 | 7 |
| Aug 27, 2002 | Day | 5-3-4 | 12 | 3 |
| Aug 26, 2002 | Night | 3-6-7 | 16 | 7 |
| Aug 26, 2002 | Day | 8-4-4 | 16 | 7 |