The winning Connecticut Play3 numbers for August 24, 2002 were: night 5-1-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 24, 2002 | Night | 5-1-4 | 10 | 1 |
| Aug 23, 2002 | Night | 0-7-1 | 8 | 8 |
| Aug 23, 2002 | Day | 8-5-1 | 14 | 5 |
| Aug 22, 2002 | Night | 4-8-8 | 20 | 2 |
| Aug 22, 2002 | Day | 7-1-2 | 10 | 1 |
| Aug 21, 2002 | Night | 5-1-4 | 10 | 1 |
| Aug 21, 2002 | Day | 8-8-3 | 19 | 1 |
| Aug 20, 2002 | Night | 6-7-7 | 20 | 2 |
| Aug 20, 2002 | Day | 5-9-7 | 21 | 3 |
| Aug 19, 2002 | Night | 7-5-3 | 15 | 6 |
| Aug 19, 2002 | Day | 5-0-9 | 14 | 5 |
| Aug 18, 2002 | Night | 3-5-0 | 8 | 8 |