The winning Connecticut Play3 numbers for August 11, 2002 were: night 9-9-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 11, 2002 | Night | 9-9-1 | 19 | 1 |
| Aug 10, 2002 | Night | 7-7-6 | 20 | 2 |
| Aug 9, 2002 | Night | 9-6-7 | 22 | 4 |
| Aug 9, 2002 | Day | 6-5-4 | 15 | 6 |
| Aug 8, 2002 | Night | 8-3-9 | 20 | 2 |
| Aug 8, 2002 | Day | 6-2-1 | 9 | 9 |
| Aug 7, 2002 | Night | 8-5-9 | 22 | 4 |
| Aug 7, 2002 | Day | 1-4-6 | 11 | 2 |
| Aug 6, 2002 | Night | 1-7-7 | 15 | 6 |
| Aug 6, 2002 | Day | 7-6-6 | 19 | 1 |
| Aug 5, 2002 | Night | 4-5-2 | 11 | 2 |
| Aug 5, 2002 | Day | 7-8-7 | 22 | 4 |