The winning Connecticut Play3 numbers for August 7, 2002 were: day 1-4-6; night 8-5-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 7, 2002 | Night | 8-5-9 | 22 | 4 |
| Aug 7, 2002 | Day | 1-4-6 | 11 | 2 |
| Aug 6, 2002 | Night | 1-7-7 | 15 | 6 |
| Aug 6, 2002 | Day | 7-6-6 | 19 | 1 |
| Aug 5, 2002 | Night | 4-5-2 | 11 | 2 |
| Aug 5, 2002 | Day | 7-8-7 | 22 | 4 |
| Aug 4, 2002 | Night | 3-5-2 | 10 | 1 |
| Aug 3, 2002 | Night | 9-0-8 | 17 | 8 |
| Aug 2, 2002 | Night | 6-0-9 | 15 | 6 |
| Aug 2, 2002 | Day | 1-9-6 | 16 | 7 |
| Aug 1, 2002 | Night | 4-3-0 | 7 | 7 |
| Aug 1, 2002 | Day | 3-7-6 | 16 | 7 |