The winning Connecticut Play3 numbers for August 3, 2002 were: night 9-0-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 3, 2002 | Night | 9-0-8 | 17 | 8 |
| Aug 2, 2002 | Night | 6-0-9 | 15 | 6 |
| Aug 2, 2002 | Day | 1-9-6 | 16 | 7 |
| Aug 1, 2002 | Night | 4-3-0 | 7 | 7 |
| Aug 1, 2002 | Day | 3-7-6 | 16 | 7 |
| Jul 31, 2002 | Night | 0-9-4 | 13 | 4 |
| Jul 31, 2002 | Day | 9-2-7 | 18 | 9 |
| Jul 30, 2002 | Night | 6-6-1 | 13 | 4 |
| Jul 30, 2002 | Day | 5-1-6 | 12 | 3 |
| Jul 29, 2002 | Night | 0-5-8 | 13 | 4 |
| Jul 29, 2002 | Day | 1-2-9 | 12 | 3 |
| Jul 28, 2002 | Night | 7-5-1 | 13 | 4 |