The winning Connecticut Play3 numbers for July 18, 2002 were: day 2-9-2; night 1-5-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jul 18, 2002 | Night | 1-5-7 | 13 | 4 |
| Jul 18, 2002 | Day | 2-9-2 | 13 | 4 |
| Jul 17, 2002 | Night | 5-4-4 | 13 | 4 |
| Jul 17, 2002 | Day | 7-6-7 | 20 | 2 |
| Jul 16, 2002 | Night | 9-7-8 | 24 | 6 |
| Jul 16, 2002 | Day | 9-6-2 | 17 | 8 |
| Jul 15, 2002 | Night | 4-9-1 | 14 | 5 |
| Jul 15, 2002 | Day | 1-6-3 | 10 | 1 |
| Jul 14, 2002 | Night | 5-1-1 | 7 | 7 |
| Jul 13, 2002 | Night | 9-6-3 | 18 | 9 |
| Jul 12, 2002 | Night | 6-5-2 | 13 | 4 |
| Jul 12, 2002 | Day | 6-8-2 | 16 | 7 |