The winning Connecticut Play3 numbers for May 18, 2002 were: night 1-0-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| May 18, 2002 | Night | 1-0-5 | 6 | 6 |
| May 17, 2002 | Night | 4-9-3 | 16 | 7 |
| May 17, 2002 | Day | 5-2-3 | 10 | 1 |
| May 16, 2002 | Night | 7-9-1 | 17 | 8 |
| May 16, 2002 | Day | 3-6-4 | 13 | 4 |
| May 15, 2002 | Night | 5-5-1 | 11 | 2 |
| May 15, 2002 | Day | 2-3-7 | 12 | 3 |
| May 14, 2002 | Night | 8-3-1 | 12 | 3 |
| May 14, 2002 | Day | 3-5-4 | 12 | 3 |
| May 13, 2002 | Night | 8-1-7 | 16 | 7 |
| May 13, 2002 | Day | 4-2-2 | 8 | 8 |
| May 12, 2002 | Night | 8-6-1 | 15 | 6 |