The winning Connecticut Play3 numbers for May 4, 2002 were: night 2-1-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| May 4, 2002 | Night | 2-1-0 | 3 | 3 |
| May 3, 2002 | Night | 7-4-6 | 17 | 8 |
| May 3, 2002 | Day | 0-5-3 | 8 | 8 |
| May 2, 2002 | Night | 6-6-3 | 15 | 6 |
| May 2, 2002 | Day | 7-1-9 | 17 | 8 |
| May 1, 2002 | Night | 2-4-3 | 9 | 9 |
| May 1, 2002 | Day | 4-1-8 | 13 | 4 |
| Apr 30, 2002 | Night | 0-2-2 | 4 | 4 |
| Apr 30, 2002 | Day | 0-6-3 | 9 | 9 |
| Apr 29, 2002 | Night | 2-8-1 | 11 | 2 |
| Apr 29, 2002 | Day | 0-7-2 | 9 | 9 |
| Apr 28, 2002 | Night | 7-7-9 | 23 | 5 |