The winning Connecticut Play3 numbers for March 23, 2002 were: night 3-6-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 23, 2002 | Night | 3-6-0 | 9 | 9 |
| Mar 22, 2002 | Night | 6-7-7 | 20 | 2 |
| Mar 22, 2002 | Day | 7-8-9 | 24 | 6 |
| Mar 21, 2002 | Night | 4-4-6 | 14 | 5 |
| Mar 21, 2002 | Day | 4-1-2 | 7 | 7 |
| Mar 20, 2002 | Night | 0-1-1 | 2 | 2 |
| Mar 20, 2002 | Day | 7-0-4 | 11 | 2 |
| Mar 19, 2002 | Night | 1-7-0 | 8 | 8 |
| Mar 19, 2002 | Day | 1-0-7 | 8 | 8 |
| Mar 18, 2002 | Night | 7-6-2 | 15 | 6 |
| Mar 18, 2002 | Day | 1-4-3 | 8 | 8 |
| Mar 17, 2002 | Night | 1-6-2 | 9 | 9 |